# A Code to Check Whether A String is An Element of The pq System or Not

#### Dolyetyus

##### International Team Director   Hi folks, I am sharing this here because maybe it will help one of you in your homework or algorithm and logic lessons et cetera.

First of all, What Is The pq System?

The pq system is a simple system of three different symbols: p, q, and (the letter p, the letter q, and the hyphen). From these three symbols, you can generate system-specific or non-system symbol sequences like p, qq-p or --p-q.

A string belongs to the system if it is an axiom or can be derived from an axiom with a rule.

The pq system has (infinitely) axioms in the following case:

• All strings in the format Xp-qX-, where X represents the same number of non-zero hyphens, are part of the system.

And one rule of thumb to generate new sequences from these axioms:

Assume that X, Y, and Z represent strings containing only hyphens. If XpYqZ is part of the system, then XpY-qZ- is part of the system

Definition from:

Code To Check The String

Python:
``````import re

hyphencounterforward=0
hyphencounterreverse=0
dashnumber=0
theorem=0
hyphennumber=0
i=0
j=0
qbefore = 0

pq=input("Enter the string: ")

p = "p" in pq
q = "q" in pq
dash= "-" in pq

if p==1 and q==1 and dash==1 and pq[-1] == "-" and pq == "-":

reversepq=pq[::-1]

text1 = pq.partition("p")
text2 = reversepq.partition("q")

hyphencounterforward=len(text1)
hyphencounterreverse=len(text2)

if hyphencounterreverse==hyphencounterforward+1:
dashnumber=1

pqorder=pq.replace("-", "")
if pqorder=="q":
qbefore=1

if qbefore==0:
hyphenbetween = re.search('p(.*)q', pq)
hyphennumber=hyphenbetween.group(1)

print()
if len(hyphennumber) >= 1:
hyphennumber=1

dashcheck=pq.replace("q", "")
dashcheck=dashcheck.replace("p", "")

if len(dashcheck)/2==hyphencounterreverse:
theorem=1

if qbefore==0 and dashnumber==1 and hyphennumber==1 or theorem==1:
print("This string is an element of the system")

else:
print("This string is not an element of the system")

else:
print("This string is not an element of the system")``````

Son düzenleme:
• Safak-Bey

#### Extazİ

##### Basın&Medya Ekibi   Nice topic.

#### Ghost Killer

##### Saldırı Timleri Genel Sorumlu     nice topic.

#### THE zoRRo

##### Uzman üye   Nice topic.

#### rootibo

##### Kıdemli Üye   Hi folks, I am sharing this here because maybe it will help one of you in your homework or algorithm and logic lessons et cetera.

First of all, What Is The pq System?

The pq system is a simple system of three different symbols: p, q, and (the letter p, the letter q, and the hyphen). From these three symbols, you can generate system-specific or non-system symbol sequences like p, qq-p or --p-q.

A string belongs to the system if it is an axiom or can be derived from an axiom with a rule.

The pq system has (infinitely) axioms in the following case:

• All strings in the format Xp-qX-, where X represents the same number of non-zero hyphens, are part of the system.

And one rule of thumb to generate new sequences from these axioms:

Assume that X, Y, and Z represent strings containing only hyphens. If XpYqZ is part of the system, then XpY-qZ- is part of the system

Definition from:

Code To Check The String

Python:
``````import re

hyphencounterforward=0
hyphencounterreverse=0
dashnumber=0
theorem=0
hyphennumber=0
i=0
j=0
qbefore = 0

pq=input("Enter the string: ")

p = "p" in pq
q = "q" in pq
dash= "-" in pq

if p==1 and q==1 and dash==1 and pq[-1] == "-" and pq == "-":

reversepq=pq[::-1]

text1 = pq.partition("p")
text2 = reversepq.partition("q")

hyphencounterforward=len(text1)
hyphencounterreverse=len(text2)

if hyphencounterreverse==hyphencounterforward+1:
dashnumber=1

pqorder=pq.replace("-", "")
if pqorder=="q":
qbefore=1

if qbefore==0:
hyphenbetween = re.search('p(.*)q', pq)
hyphennumber=hyphenbetween.group(1)

print()
if len(hyphennumber) >= 1:
hyphennumber=1

dashcheck=pq.replace("q", "")
dashcheck=dashcheck.replace("p", "")

if len(dashcheck)/2==hyphencounterreverse:
theorem=1

if qbefore==0 and dashnumber==1 and hyphennumber==1 or theorem==1:
print("This string is an element of the system")

else:
print("This string is not an element of the system")

else:
print("This string is not an element of the system")``````
very good topic .

#### QuatrexDefacer

##### Katılımcı Üye  Hi folks, I am sharing this here because maybe it will help one of you in your homework or algorithm and logic lessons et cetera.

First of all, What Is The pq System?

The pq system is a simple system of three different symbols: p, q, and (the letter p, the letter q, and the hyphen). From these three symbols, you can generate system-specific or non-system symbol sequences like p, qq-p or --p-q.

A string belongs to the system if it is an axiom or can be derived from an axiom with a rule.

The pq system has (infinitely) axioms in the following case:

• All strings in the format Xp-qX-, where X represents the same number of non-zero hyphens, are part of the system.

And one rule of thumb to generate new sequences from these axioms:

Assume that X, Y, and Z represent strings containing only hyphens. If XpYqZ is part of the system, then XpY-qZ- is part of the system

Definition from:

Code To Check The String

Python:
``````import re

hyphencounterforward=0
hyphencounterreverse=0
dashnumber=0
theorem=0
hyphennumber=0
i=0
j=0
qbefore = 0

pq=input("Enter the string: ")

p = "p" in pq
q = "q" in pq
dash= "-" in pq

if p==1 and q==1 and dash==1 and pq[-1] == "-" and pq == "-":

reversepq=pq[::-1]

text1 = pq.partition("p")
text2 = reversepq.partition("q")

hyphencounterforward=len(text1)
hyphencounterreverse=len(text2)

if hyphencounterreverse==hyphencounterforward+1:
dashnumber=1

pqorder=pq.replace("-", "")
if pqorder=="q":
qbefore=1

if qbefore==0:
hyphenbetween = re.search('p(.*)q', pq)
hyphennumber=hyphenbetween.group(1)

print()
if len(hyphennumber) >= 1:
hyphennumber=1

dashcheck=pq.replace("q", "")
dashcheck=dashcheck.replace("p", "")

if len(dashcheck)/2==hyphencounterreverse:
theorem=1

if qbefore==0 and dashnumber==1 and hyphennumber==1 or theorem==1:
print("This string is an element of the system")

else:
print("This string is not an element of the system")

else:
print("This string is not an element of the system")``````
nice topic.

#### OnlyMetee

##### Katılımcı Üye  nice topic.

#### Safak-Bey

##### Uzman üye     nice topic.

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